4/3x-3=x-4

Solution for 4/3x-3=x-4 equation:

4/3x-3=x-4

We move all terms to the left:

4/3x-3-(x-4)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

4/3x-x+4-3=0

We multiply all the terms by the denominator


-x*3x+4*3x-3*3x+4=0

Wy multiply elements

-3x^2+12x-9x+4=0

We add all the numbers together, and all the variables

-3x^2+3x+4=0

a = -3; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-3)·4
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{57}}{2*-3}=\frac{-3-\sqrt{57}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{57}}{2*-3}=\frac{-3+\sqrt{57}}{-6}
$