4/3x-5/6=-2/x

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Solution for 4/3x-5/6=-2/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/3)*x-(5/6) = -2/x // + -2/x

(4/3)*x-(-2/x)-(5/6) = 0

(4/3)*x+2*x^-1-5/6 = 0

4/3*x^1+2*x^-1-5/6*x^0 = 0

(4/3*x^2-5/6*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^2-5/6*x^1+2*x^0) = 0

x^1

(4/3)*x^2+(-5/6)*x+2 = 0

(4/3)*x^2+(-5/6)*x+2 = 0

DELTA = (-5/6)^2-(2*4*(4/3))

DELTA = -359/36

DELTA < 0

x in { } 

x belongs to the empty set

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