4/3x=5-8/x

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Solution for 4/3x=5-8/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/3)*x = 5-(8/x) // - 5-(8/x)

(4/3)*x+8/x-5 = 0

4/3*x^1+8*x^-1-5*x^0 = 0

(4/3*x^2-5*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^2-5*x^1+8*x^0) = 0

x^1

(4/3)*x^2-5*x+8 = 0

(4/3)*x^2-5*x+8 = 0

DELTA = (-5)^2-(4*8*(4/3))

DELTA = -53/3

DELTA < 0

x in { } 

x belongs to the empty set

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