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4/3x=5/6x-5
We move all terms to the left:
4/3x-(5/6x-5)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x-5)!=0We get rid of parentheses
x∈R
4/3x-5/6x+5=0
We calculate fractions
24x/18x^2+(-15x)/18x^2+5=0
We multiply all the terms by the denominator
24x+(-15x)+5*18x^2=0
Wy multiply elements
90x^2+24x+(-15x)=0
We get rid of parentheses
90x^2+24x-15x=0
We add all the numbers together, and all the variables
90x^2+9x=0
a = 90; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·90·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*90}=\frac{-18}{180} =-1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*90}=\frac{0}{180} =0 $
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