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4/3x=6x-14
We move all terms to the left:
4/3x-(6x-14)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
4/3x-6x+14=0
We multiply all the terms by the denominator
-6x*3x+14*3x+4=0
Wy multiply elements
-18x^2+42x+4=0
a = -18; b = 42; c = +4;
Δ = b2-4ac
Δ = 422-4·(-18)·4
Δ = 2052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2052}=\sqrt{36*57}=\sqrt{36}*\sqrt{57}=6\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6\sqrt{57}}{2*-18}=\frac{-42-6\sqrt{57}}{-36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6\sqrt{57}}{2*-18}=\frac{-42+6\sqrt{57}}{-36} $
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