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4/3x=x-8
We move all terms to the left:
4/3x-(x-8)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
4/3x-x+8=0
We multiply all the terms by the denominator
-x*3x+8*3x+4=0
Wy multiply elements
-3x^2+24x+4=0
a = -3; b = 24; c = +4;
Δ = b2-4ac
Δ = 242-4·(-3)·4
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{39}}{2*-3}=\frac{-24-4\sqrt{39}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{39}}{2*-3}=\frac{-24+4\sqrt{39}}{-6} $
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