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4/5(10-25x)-(4x+5)=2/3(x+6)
We move all terms to the left:
4/5(10-25x)-(4x+5)-(2/3(x+6))=0
Domain of the equation: 5(10-25x)!=0
x∈R
Domain of the equation: 3(x+6))!=0We add all the numbers together, and all the variables
x∈R
4/5(-25x+10)-(4x+5)-(2/3(x+6))=0
We get rid of parentheses
4/5(-25x+10)-4x-(2/3(x+6))-5=0
We calculate fractions
-4x+(12xx/(5(-25x+10)*3(x+6)))+(-10x0/(5(-25x+10)*3(x+6)))-5=0
We calculate terms in parentheses: +(12xx/(5(-25x+10)*3(x+6))), so:
12xx/(5(-25x+10)*3(x+6))
We multiply all the terms by the denominator
12xx
Back to the equation:
+(12xx)
We calculate terms in parentheses: +(-10x0/(5(-25x+10)*3(x+6))), so:We get rid of parentheses
-10x0/(5(-25x+10)*3(x+6))
We multiply all the terms by the denominator
-10x0
We add all the numbers together, and all the variables
-10x
Back to the equation:
+(-10x)
-4x+12xx-10x-5=0
We add all the numbers together, and all the variables
-14x+12xx-5=0
We move all terms containing x to the left, all other terms to the right
-14x+12xx=5
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