4/5(10z+10)=40

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Solution for 4/5(10z+10)=40 equation: 



4/5(10z+10)=40

We move all terms to the left:

4/5(10z+10)-(40)=0



Domain of the equation: 5(10z+10)!=0

z∈R



We multiply all the terms by the denominator


-40*5(10z+10)+4=0

Wy multiply elements

-200z(1+4=0

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