4/5(12-2v)=-2v-12

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Solution for 4/5(12-2v)=-2v-12 equation: 



4/5(12-2v)=-2v-12

We move all terms to the left:

4/5(12-2v)-(-2v-12)=0



Domain of the equation: 5(12-2v)!=0

v∈R



We add all the numbers together, and all the variables

4/5(-2v+12)-(-2v-12)=0

We get rid of parentheses

4/5(-2v+12)+2v+12=0

We multiply all the terms by the denominator


2v*5(-2v+12)+12*5(-2v+12)+4=0

Wy multiply elements

10v^2(-+60v(-+4=0

We use the square of the difference formula

10v^2(-60v(-4=0

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