4/5(15x+20)-7x=5/6(12-24)+6

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Solution for 4/5(15x+20)-7x=5/6(12-24)+6 equation: 



4/5(15x+20)-7x=5/6(12-24)+6

We move all terms to the left:

4/5(15x+20)-7x-(5/6(12-24)+6)=0



Domain of the equation: 5(15x+20)!=0

x∈R



We add all the numbers together, and all the variables

4/5(15x+20)-7x-(5/6(-12)+6)=0

We add all the numbers together, and all the variables

-7x+4/5(15x+20)-(5/6(-12)+6)=0

We calculate fractions


-7x+()/(5(15x+20)*6(-12))+(-25x1/(5(15x+20)*6(-12))=0



We calculate terms in parentheses: +()/(5(15x+20)*6(-12)), so:

)/(5(15x+20)*6(-12)

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()





We calculate terms in parentheses: +(-25x1/(5(15x+20)*6(-12)), so:

-25x1/(5(15x+20)*6(-12)

We multiply all the terms by the denominator


-25x1

We add all the numbers together, and all the variables

-25x

Back to the equation:

+(-25x)



We add all the numbers together, and all the variables

-7x+(-25x)=0

We get rid of parentheses

-7x-25x=0

We add all the numbers together, and all the variables

-32x=0

x=0/-32

x=0

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