4/5(2+m)=25

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Solution for 4/5(2+m)=25 equation: 



4/5(2+m)=25

We move all terms to the left:

4/5(2+m)-(25)=0



Domain of the equation: 5(2+m)!=0

m∈R



We add all the numbers together, and all the variables

4/5(m+2)-25=0

We multiply all the terms by the denominator


-25*5(m+2)+4=0

Wy multiply elements

-125m(m+4=0

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