4/5(20x+12)=-35

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Solution for 4/5(20x+12)=-35 equation: 



4/5(20x+12)=-35

We move all terms to the left:

4/5(20x+12)-(-35)=0



Domain of the equation: 5(20x+12)!=0

x∈R



We add all the numbers together, and all the variables

4/5(20x+12)+35=0

We multiply all the terms by the denominator


35*5(20x+12)+4=0

Wy multiply elements

175x(2+4=0

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