4/5(2y+5)=28

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Solution for 4/5(2y+5)=28 equation:



4/5(2y+5)=28
We move all terms to the left:
4/5(2y+5)-(28)=0
Domain of the equation: 5(2y+5)!=0
y∈R
We multiply all the terms by the denominator
-28*5(2y+5)+4=0
Wy multiply elements
-140y(2+4=0

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