4/5(2y-5)-2/3(2y-7)=7/15

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Solution for 4/5(2y-5)-2/3(2y-7)=7/15 equation: 



4/5(2y-5)-2/3(2y-7)=7/15

We move all terms to the left:

4/5(2y-5)-2/3(2y-7)-(7/15)=0



Domain of the equation: 5(2y-5)!=0

y∈R





Domain of the equation: 3(2y-7)!=0

y∈R



We add all the numbers together, and all the variables

4/5(2y-5)-2/3(2y-7)-(+7/15)=0

We get rid of parentheses

4/5(2y-5)-2/3(2y-7)-7/15=0

We calculate fractions


(180y2/(5(2y-5)*3(2y-7)*15)+(-150y2/(5(2y-5)*3(2y-7)*15)+(-105y^22/(5(2y-5)*3(2y-7)*15)=0



We calculate terms in parentheses: +(180y2/(5(2y-5)*3(2y-7)*15)+(-150y2/(5(2y-5)*3(2y-7)*15)+(-105y^22/(5(2y-5)*3(2y-7)*15), so:

180y2/(5(2y-5)*3(2y-7)*15)+(-150y2/(5(2y-5)*3(2y-7)*15)+(-105y^22/(5(2y-5)*3(2y-7)*15

We do not support eypression: y^22

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