4/5(3-2x)=-3(x-5)

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Solution for 4/5(3-2x)=-3(x-5) equation: 



4/5(3-2x)=-3(x-5)

We move all terms to the left:

4/5(3-2x)-(-3(x-5))=0



Domain of the equation: 5(3-2x)!=0

x∈R



We add all the numbers together, and all the variables

4/5(-2x+3)-(-3(x-5))=0

We multiply all the terms by the denominator


-((-3(x-5)))*5(-2x+3)+4=0



We calculate terms in parentheses: -((-3(x-5)))*5(-2x+3), so:

(-3(x-5)))*5(-2x+3

We add all the numbers together, and all the variables

-2x+(-3(x-5)))*5(+3

Back to the equation:

-(-2x+(-3(x-5)))*5(+3)



We add all the numbers together, and all the variables

-(-2x+(-3(x-5)))*53+4=0

We move all terms containing x to the left, all other terms to the right

-(-2x+(-3(x-5)))*53=-4

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