4/5(3-2x)=-3(x-5)

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Solution for 4/5(3-2x)=-3(x-5) equation:



4/5(3-2x)=-3(x-5)
We move all terms to the left:
4/5(3-2x)-(-3(x-5))=0
Domain of the equation: 5(3-2x)!=0
x∈R
We add all the numbers together, and all the variables
4/5(-2x+3)-(-3(x-5))=0
We multiply all the terms by the denominator
-((-3(x-5)))*5(-2x+3)+4=0
We calculate terms in parentheses: -((-3(x-5)))*5(-2x+3), so:
(-3(x-5)))*5(-2x+3
We add all the numbers together, and all the variables
-2x+(-3(x-5)))*5(+3
Back to the equation:
-(-2x+(-3(x-5)))*5(+3)
We add all the numbers together, and all the variables
-(-2x+(-3(x-5)))*53+4=0
We move all terms containing x to the left, all other terms to the right
-(-2x+(-3(x-5)))*53=-4

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