4/5(3k-2)=5/4(2k-3)

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Solution for 4/5(3k-2)=5/4(2k-3) equation: 



4/5(3k-2)=5/4(2k-3)

We move all terms to the left:

4/5(3k-2)-(5/4(2k-3))=0



Domain of the equation: 5(3k-2)!=0

k∈R





Domain of the equation: 4(2k-3))!=0

k∈R



We calculate fractions


(16k2/(5(3k-2)*4(2k-3)))+(-25k3/(5(3k-2)*4(2k-3)))=0



We calculate terms in parentheses: +(16k2/(5(3k-2)*4(2k-3))), so:

16k2/(5(3k-2)*4(2k-3))

We multiply all the terms by the denominator


16k2

We add all the numbers together, and all the variables

16k^2

Back to the equation:

+(16k^2)





We calculate terms in parentheses: +(-25k3/(5(3k-2)*4(2k-3))), so:

-25k3/(5(3k-2)*4(2k-3))

We multiply all the terms by the denominator


-25k3

We add all the numbers together, and all the variables

-25k^3

We do not support ekpression: k^3

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