4/5(3m+4)=1/3(2m-8)

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Solution for 4/5(3m+4)=1/3(2m-8) equation: 



4/5(3m+4)=1/3(2m-8)

We move all terms to the left:

4/5(3m+4)-(1/3(2m-8))=0



Domain of the equation: 5(3m+4)!=0

m∈R





Domain of the equation: 3(2m-8))!=0

m∈R



We calculate fractions


(12m2/(5(3m+4)*3(2m-8)))+(-5m3/(5(3m+4)*3(2m-8)))=0



We calculate terms in parentheses: +(12m2/(5(3m+4)*3(2m-8))), so:

12m2/(5(3m+4)*3(2m-8))

We multiply all the terms by the denominator


12m2

We add all the numbers together, and all the variables

12m^2

Back to the equation:

+(12m^2)





We calculate terms in parentheses: +(-5m3/(5(3m+4)*3(2m-8))), so:

-5m3/(5(3m+4)*3(2m-8))

We multiply all the terms by the denominator


-5m3

We add all the numbers together, and all the variables

-5m^3

We do not support empression: m^3

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