4/5(3x/2-5)(10x-2)=0

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Solution for 4/5(3x/2-5)(10x-2)=0 equation: 


x in (-oo:+oo)

(4/5)*((3*x)/2-5)*(10*x-2) = 0

4/5*(3/2*x-5)*(10*x-2) = 0

( 10*x-2 )

10*x-2 = 0 // + 2

10*x = 2 // : 10

x = 2/10

x = 1/5

( 3/2*x-5 )

3/2*x-5 = 0 // + 5

3/2*x = 5 // : 3/2

x = 5/3/2

x = 10/3

( 4/5 )

4/5 = 0

x belongs to the empty set

x in { 1/5, 10/3 }

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