4/5(40x+30)-4=-3/4(16x-36)

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Solution for 4/5(40x+30)-4=-3/4(16x-36) equation: 



4/5(40x+30)-4=-3/4(16x-36)

We move all terms to the left:

4/5(40x+30)-4-(-3/4(16x-36))=0



Domain of the equation: 5(40x+30)!=0

x∈R





Domain of the equation: 4(16x-36))!=0

x∈R



We calculate fractions


(16x1/(5(40x+30)*4(16x-36)))+(-(-15x4)/(5(40x+30)*4(16x-36)))-4=0



We calculate terms in parentheses: +(16x1/(5(40x+30)*4(16x-36))), so:

16x1/(5(40x+30)*4(16x-36))

We multiply all the terms by the denominator


16x1

We add all the numbers together, and all the variables

16x

Back to the equation:

+(16x)





We calculate terms in parentheses: +(-(-15x4)/(5(40x+30)*4(16x-36))), so:

-(-15x4)/(5(40x+30)*4(16x-36))

We add all the numbers together, and all the variables

-(-15x^4)/(5(40x+30)*4(16x-36))

We multiply all the terms by the denominator


-(-15x^4)

We do not support expression: x^4

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