4/5(7y+3)=10

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Solution for 4/5(7y+3)=10 equation: 



4/5(7y+3)=10

We move all terms to the left:

4/5(7y+3)-(10)=0



Domain of the equation: 5(7y+3)!=0

y∈R



We multiply all the terms by the denominator


-10*5(7y+3)+4=0

Wy multiply elements

-50y(7+4=0

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