If it's not what You are looking for type in the equation solver your own equation and let us solve it.
c in (-oo:+oo)
(4/5)*(8-(2*c)) = 0
(4/5)*(8-2*c) = 0
4/5*(8-2*c) = 0
( 4/5 )
4/5 = 0
c belongs to the empty set
( 8-2*c )
8-2*c = 0 // - 8
-2*c = -8 // : -2
c = -8/(-2)
c = 4
c = 4
| x+3=-12+8 | | 2=2-3x | | 9(m-2)=m-40 | | 17=9-6/5(y) | | 5x=22+3 | | 3(4x+8)=12(6x-3)+2 | | -(12x-6)=12+6 | | 1+3v+10= | | n^2-3n=-40 | | -4x+17=35 | | -4(8v-6)+5v=-6(-4+8v) | | y=cot^2(sint) | | 4x-6y=23 | | X^2+6x+2x+12=0 | | 2/9×5/7 | | -k+3=13 | | (6-v)(3v+5)=0 | | 118+5x+4x-1=180 | | (4x)(3)=(5)(1) | | 5-2(4-3x)=9 | | -7(-4+5x)=-3x-4 | | 2981.1x=6378.1 | | -37-8k=-5(2+7k) | | 2/9x4/6 | | -5.4-0.6d=-23.4 | | 1/3x4/6 | | 12x+8+16-3x-4x=10 | | 1-5x=-8-8x | | ys+yv=r | | x^2-23x=30 | | -1+x=.3 | | 5/x=125 |