4/5(b-5)=32

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Solution for 4/5(b-5)=32 equation: 



4/5(b-5)=32

We move all terms to the left:

4/5(b-5)-(32)=0



Domain of the equation: 5(b-5)!=0

b∈R



We multiply all the terms by the denominator


-32*5(b-5)+4=0

Wy multiply elements

-160b(b+4=0

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