4/5(g+3)=6+2/7g

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Solution for 4/5(g+3)=6+2/7g equation: 



4/5(g+3)=6+2/7g

We move all terms to the left:

4/5(g+3)-(6+2/7g)=0



Domain of the equation: 5(g+3)!=0

g∈R





Domain of the equation: 7g)!=0

g!=0/1

g!=0

g∈R



We add all the numbers together, and all the variables

4/5(g+3)-(2/7g+6)=0

We get rid of parentheses

4/5(g+3)-2/7g-6=0

We calculate fractions


28g/(35g^2+105g)+(-10gg/(35g^2+105g)-6=0

We calculate fractions

We do not support egpression: g^3

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