4/5(n-3)=1-2

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Solution for 4/5(n-3)=1-2 equation: 



4/5(n-3)=1-2

We move all terms to the left:

4/5(n-3)-(1-2)=0



Domain of the equation: 5(n-3)!=0

n∈R



We add all the numbers together, and all the variables

4/5(n-3)-(-1)=0

We add all the numbers together, and all the variables

4/5(n-3)+1=0

We multiply all the terms by the denominator


1*5(n-3)+4=0

Wy multiply elements

5n(n+4=0

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