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4/5(x+4)=1/8(x+4)
We move all terms to the left:
4/5(x+4)-(1/8(x+4))=0
Domain of the equation: 5(x+4)!=0
x∈R
Domain of the equation: 8(x+4))!=0We calculate fractions
x∈R
(32xx/(5(x+4)*8(x+4)))+(-5xx/(5(x+4)*8(x+4)))=0
We calculate terms in parentheses: +(32xx/(5(x+4)*8(x+4))), so:
32xx/(5(x+4)*8(x+4))
We multiply all the terms by the denominator
32xx
Back to the equation:
+(32xx)
We calculate terms in parentheses: +(-5xx/(5(x+4)*8(x+4))), so:We get rid of parentheses
-5xx/(5(x+4)*8(x+4))
We multiply all the terms by the denominator
-5xx
Back to the equation:
+(-5xx)
32xx-5xx=0
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