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4/5+3/(4x)=-1/(6x)
We move all terms to the left:
4/5+3/(4x)-(-1/(6x))=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
3/4x+1/6x+4/5=0
We calculate fractions
576x^2/600x^2+450x/600x^2+100x/600x^2=0
We multiply all the terms by the denominator
576x^2+450x+100x=0
We add all the numbers together, and all the variables
576x^2+550x=0
a = 576; b = 550; c = 0;
Δ = b2-4ac
Δ = 5502-4·576·0
Δ = 302500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{302500}=550$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(550)-550}{2*576}=\frac{-1100}{1152} =-275/288 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(550)+550}{2*576}=\frac{0}{1152} =0 $
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