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4/5a-3/2a=-1
We move all terms to the left:
4/5a-3/2a-(-1)=0
Domain of the equation: 5a!=0
a!=0/5
a!=0
a∈R
Domain of the equation: 2a!=0We add all the numbers together, and all the variables
a!=0/2
a!=0
a∈R
4/5a-3/2a+1=0
We calculate fractions
8a/10a^2+(-15a)/10a^2+1=0
We multiply all the terms by the denominator
8a+(-15a)+1*10a^2=0
Wy multiply elements
10a^2+8a+(-15a)=0
We get rid of parentheses
10a^2+8a-15a=0
We add all the numbers together, and all the variables
10a^2-7a=0
a = 10; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·10·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*10}=\frac{0}{20} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*10}=\frac{14}{20} =7/10 $
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