4/5c+12=32

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Solution for 4/5c+12=32 equation: 



4/5c+12=32

We move all terms to the left:

4/5c+12-(32)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

4/5c-20=0

We multiply all the terms by the denominator


-20*5c+4=0

Wy multiply elements

-100c+4=0

We move all terms containing c to the left, all other terms to the right

-100c=-4

c=-4/-100

c=1/25

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