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4/5e-4=2/3e
We move all terms to the left:
4/5e-4-(2/3e)=0
Domain of the equation: 5e!=0
e!=0/5
e!=0
e∈R
Domain of the equation: 3e)!=0We add all the numbers together, and all the variables
e!=0/1
e!=0
e∈R
4/5e-(+2/3e)-4=0
We get rid of parentheses
4/5e-2/3e-4=0
We calculate fractions
12e/15e^2+(-10e)/15e^2-4=0
We multiply all the terms by the denominator
12e+(-10e)-4*15e^2=0
Wy multiply elements
-60e^2+12e+(-10e)=0
We get rid of parentheses
-60e^2+12e-10e=0
We add all the numbers together, and all the variables
-60e^2+2e=0
a = -60; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-60)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-60}=\frac{-4}{-120} =1/30 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-60}=\frac{0}{-120} =0 $
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