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4/5k-(k+1/3)=1/5(k+3)
We move all terms to the left:
4/5k-(k+1/3)-(1/5(k+3))=0
Domain of the equation: 5k!=0
k!=0/5
k!=0
k∈R
Domain of the equation: 5(k+3))!=0We add all the numbers together, and all the variables
k∈R
4/5k-(+k+1/3)-(1/5(k+3))=0
We get rid of parentheses
4/5k-k-(1/5(k+3))-1/3=0
We calculate fractions
(60kk/(75k^2k+(-(1*5k*3)/(75k^2k+(-125k^2)/(75k^2k-k=0
We can not solve this equation
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