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4/5x+1.6=x
We move all terms to the left:
4/5x+1.6-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+4/5x+1.6=0
We multiply all the terms by the denominator
-1x*5x+(1.6)*5x+4=0
We multiply parentheses
-1x*5x+8x+4=0
Wy multiply elements
-5x^2+8x+4=0
a = -5; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·(-5)·4
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12}{2*-5}=\frac{-20}{-10} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12}{2*-5}=\frac{4}{-10} =-2/5 $
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