4/5x+1/10x=36

Solution for 4/5x+1/10x=36 equation:

4/5x+1/10x=36

We move all terms to the left:

4/5x+1/10x-(36)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We calculate fractions


40x/50x^2+5x/50x^2-36=0

We multiply all the terms by the denominator


40x+5x-36*50x^2=0

We add all the numbers together, and all the variables

45x-36*50x^2=0

Wy multiply elements

-1800x^2+45x=0

a = -1800; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·(-1800)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*-1800}=\frac{-90}{-3600}
=1/40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*-1800}=\frac{0}{-3600}
=0
$