4/5x+1/3x=50

Solution for 4/5x+1/3x=50 equation:

4/5x+1/3x=50

We move all terms to the left:

4/5x+1/3x-(50)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


12x/15x^2+5x/15x^2-50=0

We multiply all the terms by the denominator


12x+5x-50*15x^2=0

We add all the numbers together, and all the variables

17x-50*15x^2=0

Wy multiply elements

-750x^2+17x=0

a = -750; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-750)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-750}=\frac{-34}{-1500}
=17/750
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-750}=\frac{0}{-1500}
=0
$