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4/5x+1/5x-1/3x=10/3
We move all terms to the left:
4/5x+1/5x-1/3x-(10/3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4/5x+1/5x-1/3x-(+10/3)=0
We get rid of parentheses
4/5x+1/5x-1/3x-10/3=0
We calculate fractions
(27x+4)/135x^2+(-5x)/135x^2+(-50x)/135x^2=0
We multiply all the terms by the denominator
(27x+4)+(-5x)+(-50x)=0
We get rid of parentheses
27x-5x-50x+4=0
We add all the numbers together, and all the variables
-28x+4=0
We move all terms containing x to the left, all other terms to the right
-28x=-4
x=-4/-28
x=1/7
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