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4/5x+10=42
We move all terms to the left:
4/5x+10-(42)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4/5x-32=0
We multiply all the terms by the denominator
-32*5x+4=0
Wy multiply elements
-160x+4=0
We move all terms containing x to the left, all other terms to the right
-160x=-4
x=-4/-160
x=1/40
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