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4/5x+1=-9/10x+4
We move all terms to the left:
4/5x+1-(-9/10x+4)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x+4)!=0We get rid of parentheses
x∈R
4/5x+9/10x-4+1=0
We calculate fractions
40x/50x^2+45x/50x^2-4+1=0
We add all the numbers together, and all the variables
40x/50x^2+45x/50x^2-3=0
We multiply all the terms by the denominator
40x+45x-3*50x^2=0
We add all the numbers together, and all the variables
85x-3*50x^2=0
Wy multiply elements
-150x^2+85x=0
a = -150; b = 85; c = 0;
Δ = b2-4ac
Δ = 852-4·(-150)·0
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-85}{2*-150}=\frac{-170}{-300} =17/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+85}{2*-150}=\frac{0}{-300} =0 $
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