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4/5x+1=3/5x-3x
We move all terms to the left:
4/5x+1-(3/5x-3x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x-3x)!=0We add all the numbers together, and all the variables
x∈R
4/5x-(-3x+3/5x)+1=0
We get rid of parentheses
4/5x+3x-3/5x+1=0
We multiply all the terms by the denominator
3x*5x+1*5x+4-3=0
We add all the numbers together, and all the variables
3x*5x+1*5x+1=0
Wy multiply elements
15x^2+5x+1=0
a = 15; b = 5; c = +1;
Δ = b2-4ac
Δ = 52-4·15·1
Δ = -35
Delta is less than zero, so there is no solution for the equation
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