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4/5x+2/3+1/5x=x
We move all terms to the left:
4/5x+2/3+1/5x-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+4/5x+1/5x+2/3=0
We calculate fractions
There is no solution for this equation
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