4/5x+3=-1/4x-1=

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Solution for 4/5x+3=-1/4x-1= equation:



4/5x+3=-1/4x-1=
We move all terms to the left:
4/5x+3-(-1/4x-1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x-1)!=0
x∈R
We get rid of parentheses
4/5x+1/4x+1+3=0
We calculate fractions
16x/20x^2+5x/20x^2+1+3=0
We add all the numbers together, and all the variables
16x/20x^2+5x/20x^2+4=0
We multiply all the terms by the denominator
16x+5x+4*20x^2=0
We add all the numbers together, and all the variables
21x+4*20x^2=0
Wy multiply elements
80x^2+21x=0
a = 80; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·80·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*80}=\frac{-42}{160} =-21/80 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*80}=\frac{0}{160} =0 $

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