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4/5x+7=3/15x+3
We move all terms to the left:
4/5x+7-(3/15x+3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 15x+3)!=0We get rid of parentheses
x∈R
4/5x-3/15x-3+7=0
We calculate fractions
60x/75x^2+(-15x)/75x^2-3+7=0
We add all the numbers together, and all the variables
60x/75x^2+(-15x)/75x^2+4=0
We multiply all the terms by the denominator
60x+(-15x)+4*75x^2=0
Wy multiply elements
300x^2+60x+(-15x)=0
We get rid of parentheses
300x^2+60x-15x=0
We add all the numbers together, and all the variables
300x^2+45x=0
a = 300; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·300·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*300}=\frac{-90}{600} =-3/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*300}=\frac{0}{600} =0 $
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