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4/5x+x=252
We move all terms to the left:
4/5x+x-(252)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
x+4/5x-252=0
We multiply all the terms by the denominator
x*5x-252*5x+4=0
Wy multiply elements
5x^2-1260x+4=0
a = 5; b = -1260; c = +4;
Δ = b2-4ac
Δ = -12602-4·5·4
Δ = 1587520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1587520}=\sqrt{7744*205}=\sqrt{7744}*\sqrt{205}=88\sqrt{205}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1260)-88\sqrt{205}}{2*5}=\frac{1260-88\sqrt{205}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1260)+88\sqrt{205}}{2*5}=\frac{1260+88\sqrt{205}}{10} $
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