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4/5x-10=42
We move all terms to the left:
4/5x-10-(42)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4/5x-52=0
We multiply all the terms by the denominator
-52*5x+4=0
Wy multiply elements
-260x+4=0
We move all terms containing x to the left, all other terms to the right
-260x=-4
x=-4/-260
x=1/65
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