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4/5x-11/3=21/3x-3
We move all terms to the left:
4/5x-11/3-(21/3x-3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x-3)!=0We get rid of parentheses
x∈R
4/5x-21/3x+3-11/3=0
We calculate fractions
108x/135x^2+(-105x)/135x^2+(-55x)/135x^2+3=0
We multiply all the terms by the denominator
108x+(-105x)+(-55x)+3*135x^2=0
Wy multiply elements
405x^2+108x+(-105x)+(-55x)=0
We get rid of parentheses
405x^2+108x-105x-55x=0
We add all the numbers together, and all the variables
405x^2-52x=0
a = 405; b = -52; c = 0;
Δ = b2-4ac
Δ = -522-4·405·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-52}{2*405}=\frac{0}{810} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+52}{2*405}=\frac{104}{810} =52/405 $
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