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4/5x-3/4=3/10x-1
We move all terms to the left:
4/5x-3/4-(3/10x-1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x-1)!=0We get rid of parentheses
x∈R
4/5x-3/10x+1-3/4=0
We calculate fractions
(-150x^2)/800x^2+640x/800x^2+(-240x)/800x^2+1=0
We multiply all the terms by the denominator
(-150x^2)+640x+(-240x)+1*800x^2=0
Wy multiply elements
(-150x^2)+800x^2+640x+(-240x)=0
We get rid of parentheses
-150x^2+800x^2+640x-240x=0
We add all the numbers together, and all the variables
650x^2+400x=0
a = 650; b = 400; c = 0;
Δ = b2-4ac
Δ = 4002-4·650·0
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{160000}=400$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-400}{2*650}=\frac{-800}{1300} =-8/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+400}{2*650}=\frac{0}{1300} =0 $
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