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4/5x-3/5x-4=8
We move all terms to the left:
4/5x-3/5x-4-(8)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4/5x-3/5x-12=0
We multiply all the terms by the denominator
-12*5x+4-3=0
We add all the numbers together, and all the variables
-12*5x+1=0
Wy multiply elements
-60x+1=0
We move all terms containing x to the left, all other terms to the right
-60x=-1
x=-1/-60
x=1/60
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