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4/5x-6=2/3x-8
We move all terms to the left:
4/5x-6-(2/3x-8)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x-8)!=0We get rid of parentheses
x∈R
4/5x-2/3x+8-6=0
We calculate fractions
12x/15x^2+(-10x)/15x^2+8-6=0
We add all the numbers together, and all the variables
12x/15x^2+(-10x)/15x^2+2=0
We multiply all the terms by the denominator
12x+(-10x)+2*15x^2=0
Wy multiply elements
30x^2+12x+(-10x)=0
We get rid of parentheses
30x^2+12x-10x=0
We add all the numbers together, and all the variables
30x^2+2x=0
a = 30; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·30·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*30}=\frac{-4}{60} =-1/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*30}=\frac{0}{60} =0 $
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