If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1*x^3+7*x^2+4*x-12 = 0;x
x
10*a-(5*b)-2;a+b-0.5
(-x)^4+2*x^2-1 = 0;x
x
6;7;2;3;0;0
{root[3][27]}
| -3(6+5n)=-30-3n | | 8(x-12)=64 | | -1x-20=18+x | | 104=4(7x-2) | | 6(n-7)=-8n+28 | | m(10)=3.5(10)+472 | | 10-4=8 | | -41=-18-8 | | -1x+20=18+x | | 11(x+5)=66 | | 4s=13.6 | | 7(4-t)=-8 | | x*2/3 | | 4x-2(-3+6x)=-2 | | 14w-17w=24 | | 7(4-t)=8 | | x*2/3=100 | | 8(3-8r)+4=156 | | b^2+b-15=0 | | 1/4(60=16s)=15=4s | | y=0.015x+9 | | w+(3/2)=(5/8) | | 5(x-16)=-60 | | 21=12-3x | | 3(2X-5Y)+5(X-3Y)= | | Y-24=2(x-8) | | -13+10x=4x+11 | | 2/10=y/100 | | -8(x-4)=-48 | | -3v+25=14+8v | | x(x+2)=11 | | -4q=-4-6q |