4/5x=27

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Solution for 4/5x=27 equation: 



4/5x=27

We move all terms to the left:

4/5x-(27)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We multiply all the terms by the denominator


-27*5x+4=0

Wy multiply elements

-135x+4=0

We move all terms containing x to the left, all other terms to the right

-135x=-4

x=-4/-135

x=4/135

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