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4/5x=2x-14
We move all terms to the left:
4/5x-(2x-14)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
4/5x-2x+14=0
We multiply all the terms by the denominator
-2x*5x+14*5x+4=0
Wy multiply elements
-10x^2+70x+4=0
a = -10; b = 70; c = +4;
Δ = b2-4ac
Δ = 702-4·(-10)·4
Δ = 5060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5060}=\sqrt{4*1265}=\sqrt{4}*\sqrt{1265}=2\sqrt{1265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{1265}}{2*-10}=\frac{-70-2\sqrt{1265}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{1265}}{2*-10}=\frac{-70+2\sqrt{1265}}{-20} $
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