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4/5x=x-5
We move all terms to the left:
4/5x-(x-5)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
4/5x-x+5=0
We multiply all the terms by the denominator
-x*5x+5*5x+4=0
Wy multiply elements
-5x^2+25x+4=0
a = -5; b = 25; c = +4;
Δ = b2-4ac
Δ = 252-4·(-5)·4
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{705}}{2*-5}=\frac{-25-\sqrt{705}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{705}}{2*-5}=\frac{-25+\sqrt{705}}{-10} $
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